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Re: Low precision exponentiation
- To: mathgroup at smc.vnet.net
- Subject: [mg129841] Re: Low precision exponentiation
- From: Sseziwa Mukasa <mukasa at gmail.com>
- Date: Mon, 18 Feb 2013 06:01:03 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-newout@smc.vnet.net
- Delivered-to: mathgroup-newsend@smc.vnet.net
- References: <20130217090833.8CF776937@smc.vnet.net>
Mathematica interprets numbers entered as decimals as machine precision.
The easiest but not only way to get a high precision answer to your
problem is to enter a rational: N[(5/2)^125,30].
Regards,
Sseziwa
On Sunday, February 17, 2013, Blaise F Egan wrote:
> I am trying to evaluate 2.5^125 to high precision.
>
> R gives 5.527147875260445183346e+49 as the answer but Mathematica with
> N[2.5^125,30] gives 5.52715*10^49 and says that is to machine precision.
>
> I am inexperienced at Mathematica. Am I doing something silly?
>
> Blaise
>
>
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