MathGroup Archive 2013

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Low precision exponentiation

  • To: mathgroup at smc.vnet.net
  • Subject: [mg129841] Re: Low precision exponentiation
  • From: Sseziwa Mukasa <mukasa at gmail.com>
  • Date: Mon, 18 Feb 2013 06:01:03 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • Delivered-to: l-mathgroup@wolfram.com
  • Delivered-to: mathgroup-newout@smc.vnet.net
  • Delivered-to: mathgroup-newsend@smc.vnet.net
  • References: <20130217090833.8CF776937@smc.vnet.net>

Mathematica interprets numbers entered as decimals as machine precision.
 The easiest but not only way to get a high precision answer to your
problem is to enter a rational: N[(5/2)^125,30].

Regards,
Sseziwa

On Sunday, February 17, 2013, Blaise F Egan wrote:

> I am trying to evaluate 2.5^125 to high precision.
>
> R gives 5.527147875260445183346e+49 as the answer but Mathematica with
> N[2.5^125,30] gives 5.52715*10^49 and says that is to machine precision.
>
> I am inexperienced at Mathematica. Am I doing something silly?
>
> Blaise
>
>


  • Prev by Date: Re: Stephen Wolfram's recent blog
  • Next by Date: Re: Low precision exponentiation
  • Previous by thread: Low precision exponentiation
  • Next by thread: Re: Low precision exponentiation