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Re: Re: Animate Command and Vector Reference

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  • Subject: [mg131438] Re: Re: Animate Command and Vector Reference
  • From: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
  • Date: Sat, 6 Jul 2013 05:03:26 -0400 (EDT)
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This is a scoping issue. The a used in the Animate iterator is local to the
Animate.


sub = {{a, 1}, {a^2, 1}};


OK, Bob, and  why this

sub[a_]:={{a,1},{a^2,1}};


Animate[Graphics[{Line[{{0,0},sub[a][[1]]/.a->aa}]}],{{aa,-1,"a"},-1,1}]

In version 6 this worked perfectly. What happened since?

Best regards, Alexei



This is a scoping issue. The a used in the Animate iterator is local to the
Animate.


sub = {{a, 1}, {a^2, 1}};


Animate[
 Graphics[{
   Line[{{0, 0}, sub[[1]] /. a -> aa}]
   }],
 {{aa, -1, "a"}, -1, 1}]



Bob Hanlon

On Wed, Jul 3, 2013 at 4:59 AM, William Dickinson <
william.dickinson.0718 at gmail.com> wrote:

> I'm new to Mathematica and I want to create some animations. I tried
> something like this:
>
> sub = {{a, 1}, {a^2, 1}}
> Animate[Graphics[{Line[{{0, 0}, sub[[1]]}]}], {a, -1, 1}]
>
> and Mathematica give me an error. This error ( Coordinate {a, 1} should be
> a pair of numbers, or a Scaled or Offset form.) is not helpful.
>
> I know that I can fix this by changing sub[[1]] to {a,1}, but this is not
> a great solution. I have several places in the actual Animate command that
> use sub[[1]] (some in conjunction with a Table command) and it would be
> painful to do all of the replacing and rewriting. How can I make something
> like this work?
>
> I suspect that I'm missing something simple....
>
>
> Thanks in advance!
>
> Will
>
>
>

Alexei BOULBITCH, Dr., habil.
IEE S.A.
ZAE Weiergewan,
11, rue Edmond Reuter,
L-5326 Contern, LUXEMBOURG

Office phone :  +352-2454-2566
Office fax:       +352-2454-3566
mobile phone:  +49 151 52 40 66 44

e-mail: alexei.boulbitch at iee.lu






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