Re: f'[0]=0.5 is True?
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- Subject: [mg131409] Re: f'[0]=0.5 is True?
- From: Daniel <dosadchy at its.jnj.com>
- Date: Sat, 20 Jul 2013 05:59:34 -0400 (EDT)
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You probably wrote at some point f'[0]=0.5 (instead of f'[0]==0.5) and Clear[f] does not remove this.
Use Remove[f] instead.
Another thing: it is a good idea to use Clear[] and Remove[] before your code, not in the middle.
This code reproduces your problem:
f'[0] = 0.5;(* introduce the error *)
eqn = f''[x] + 2 f'[x] + 30 f[x] == 0;
Clear[f];
Clear[x];
eqn1 = f[0] == 1;
eqn2 = f'[0] == 0.5;
DSolve[{eqn, eqn1, eqn2}, f[x], x]
This code works:
f'[0] = 0.5;(* introduce the error *)
Remove[f];
Clear[x];
eqn = f''[x] + 2 f'[x] + 30 f[x] == 0;
eqn1 = f[0] == 1;
eqn2 = f'[0] == 0.5;
DSolve[{eqn, eqn1, eqn2}, f[x], x]
> Dear All,
>
> I'm trying a simple exercise:
>
> eqn = f''[x] + 2 f'[x] + 30 f[x] == 0;
> Clear[f];
> Clear[x];
> eqn1 = f[0] == 1;
> eqn2 = f'[0] == 0.5;
> DSolve[{eqn, eqn1, eqn2}, f[x], x]
>
>
> and I get:
> DSolve::deqn: Equation or list of equations expected
> instead of True in the first argument {30 f[x]+2
> (f^\[Prime])[x]+(f^\[Prime]\[Prime])[x]==0,f[0]==1,Tru
> e}. >>
>
> so f'[0]=0.5 is True for Mathematica?
>
> How can it be?
>
> If I remove eqn2 from DSolve then I get a solution
> with a parameter of course.
>
> Cheers,
>
> Mariusz
>