Re: Calculating a simple integral

*To*: mathgroup at smc.vnet.net*Subject*: [mg131081] Re: Calculating a simple integral*From*: "djmpark" <djmpark at comcast.net>*Date*: Mon, 10 Jun 2013 04:11:03 -0400 (EDT)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-outx@smc.vnet.net*Delivered-to*: mathgroup-newsendx@smc.vnet.net*References*: <7586978.94875.1370767085206.JavaMail.root@m06>

Doesn't this have a singularity at 2 Pi that produces non-convergence? It's similar to: Integrate[1/x^2, {x, \[Epsilon], \[Infinity]}, Assumptions -> \[Epsilon] > 0] 1/\[Epsilon] That diverges as epsilon -> 0. Are you sure you copied the integral correctly? David Park djmpark at comcast.net http://home.comcast.net/~djmpark/index.html From: dsmirnov90 at gmail.com [mailto:dsmirnov90 at gmail.com] If there is a way to calculate with Mathematica the following integral: in = -((-1 + Cos[kz])/(kz^2 (kr^2 + kz^2)^2 (kz^2 - 4 \[Pi]^2)^2)) Integrate[in, {kz, -Infinity, Infinity}, Assumptions -> kr > 0] Another system calculates the same integral instantly. :) Thanks for any suggestions.

**Follow-Ups**:**Re: Calculating a simple integral***From:*Andrzej Kozlowski <akozlowski@gmail.com>