Re: Calculating a simple integral
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- Subject: [mg131095] Re: Calculating a simple integral
- From: Andrzej Kozlowski <akozlowski at gmail.com>
- Date: Tue, 11 Jun 2013 02:30:31 -0400 (EDT)
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No, it's similar to: Integrate[(1 - Cos[x])/(x^2*(x^2 - 4*Pi^2)^2), {x, -Infinity, Infinity}] 3/(32*Pi^3) On 10 Jun 2013, at 10:11, djmpark <djmpark at comcast.net> wrote: > Doesn't this have a singularity at 2 Pi that produces non-convergence? It's > similar to: > > Integrate[1/x^2, {x, \[Epsilon], \[Infinity]}, > Assumptions -> \[Epsilon] > 0] > > 1/\[Epsilon] > > That diverges as epsilon -> 0. > > Are you sure you copied the integral correctly? > > > David Park > djmpark at comcast.net > http://home.comcast.net/~djmpark/index.html > > > > From: dsmirnov90 at gmail.com [mailto:dsmirnov90 at gmail.com] > > > If there is a way to calculate with Mathematica the following integral: > > in = -((-1 + Cos[kz])/(kz^2 (kr^2 + kz^2)^2 (kz^2 - 4 \[Pi]^2)^2)) > Integrate[in, {kz, -Infinity, Infinity}, Assumptions -> kr > 0] > > Another system calculates the same integral instantly. :) > > Thanks for any suggestions. > >
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- Re: Calculating a simple integral
- From: "djmpark" <djmpark@comcast.net>
- Re: Calculating a simple integral