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Re: Calculating a simple integral

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  • Subject: [mg131095] Re: Calculating a simple integral
  • From: Andrzej Kozlowski <akozlowski at gmail.com>
  • Date: Tue, 11 Jun 2013 02:30:31 -0400 (EDT)
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No, it's similar to:

Integrate[(1 -
    Cos[x])/(x^2*(x^2 - 4*Pi^2)^2), {x, -Infinity, Infinity}]

3/(32*Pi^3)



On 10 Jun 2013, at 10:11, djmpark <djmpark at comcast.net> wrote:

> Doesn't this have a singularity at 2 Pi that produces non-convergence? It's
> similar to:
>
> Integrate[1/x^2, {x, \[Epsilon], \[Infinity]},
> Assumptions -> \[Epsilon] > 0]
>
> 1/\[Epsilon]
>
> That diverges as epsilon -> 0.
>
> Are you sure you copied the integral correctly?
>
>
> David Park
> djmpark at comcast.net
> http://home.comcast.net/~djmpark/index.html
>
>
>
> From: dsmirnov90 at gmail.com [mailto:dsmirnov90 at gmail.com]
>
>
> If there is a way to calculate with Mathematica the following integral:
>
> in = -((-1 + Cos[kz])/(kz^2 (kr^2 + kz^2)^2 (kz^2 - 4 \[Pi]^2)^2))
> Integrate[in, {kz, -Infinity, Infinity}, Assumptions -> kr > 0]
>
> Another system calculates the same integral instantly. :)
>
> Thanks for any suggestions.
>
>




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