Russian Peasant Multiplication / was question on how to do this
- To: undisclosed-recipients:;
- Subject: [mg131330] Russian Peasant Multiplication / was question on how to do this
- From: Richard Fateman <fateman at cs.berkeley.edu>
- Date: Sat, 29 Jun 2013 04:54:30 -0400 (EDT)
- Approved: Steven M. Christensen <steve@smc.vnet.net>, Moderator
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-outx@smc.vnet.net
- Delivered-to: mathgroup-newsendx@smc.vnet.net
- Newsgroups: comp.soft-sys.math.mathematica
Dave -- 1. You should try to come up with a useful subject line in the future. 2. It is called Russian Peasant Multiplication (which you may find on Google). 3. There is no reason to believe that a procedural algorithm has a formula, but in this case I think the inverse is known as division :)