Re: Output display by slide

• To: mathgroup at smc.vnet.net
• Subject: [mg131776] Re: Output display by slide
• From: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
• Date: Wed, 2 Oct 2013 05:54:56 -0400 (EDT)
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```a=3; b=2.5;  c=2 ;
(*  Given triangle vertices are {(0,0),(x1,y1),(x2,y2)} = { (0,0),(a,0),(b,c) } to find CG  *)
v1=Graphics[Circle[{0,0},{.03,.03}]];v2=Graphics[Circle[{a,0},{.03,.03}]];v3=Graphics[Circle[{b,c},{.03,.03}]];
x1=a;y1=0;x2=b;y2=c; {XF,YF}={x1+x2, y1+y2}/3;
CG=Graphics[Disk[{XF,YF},{.05,.05} ]];
Triang=Graphics[Line[{{0,0},{a,0},{b,c},{0,0},{XF,YF},{a,0},{XF,YF},{b,c},{XF,YF},{0,0}}] ] ;
bb=Show[{v1,v2,v3,Triang,CG},GridLines->Automatic,Axes-> True ,AspectRatio-> Automatic, PlotLabel-> "Centre of Gravity"]

How  to vary b value in a SlideView or Manipulate, say between 0 to 4, (along horizontal line y =2) to display Centre of Gravity  like it is in GSP or in Java mode ?

TIA,
Narasimham

Hi, Narasimham,

Try this for the SlideView:

SlideView[
Table[a = 3; c = 2;
(*Given triangle vertices are {(0,0),(x1,y1),(x2,y2)}={(0,0),(a,
0),(b,c)} to find CG*)
v1 = Graphics[Circle[{0, 0}, {.03, .03}]];
v2 = Graphics[Circle[{a, 0}, {.03, .03}]];
v3 = Graphics[Circle[{b, c}, {.03, .03}]];
x1 = a; y1 = 0; x2 = b; y2 = c; {XF, YF} = {x1 + x2, y1 + y2}/3;
CG = Graphics[Disk[{XF, YF}, {.05, .05}]];
Triang =
Graphics[
Line[{{0, 0}, {a, 0}, {b, c}, {0, 0}, {XF, YF}, {a, 0}, {XF,
YF}, {b, c}, {XF, YF}, {0, 0}}]];
bb = Show[{v1, v2, v3, Triang, CG}, GridLines -> Automatic,
Axes -> True, AspectRatio -> Automatic,
PlotLabel -> "Centre of Gravity"], {b, 0, 4, 0.5}]
]

Or this for Manipulate:

Manipulate[a = 3; c = 2;
(*Given triangle vertices are \
{(0,0),(x1,y1),(x2,y2)}={(0,0),(a,0),(b,c)} to find CG*)
v1 = Graphics[Circle[{0, 0}, {.03, .03}]];
v2 = Graphics[Circle[{a, 0}, {.03, .03}]];
v3 = Graphics[Circle[{b, c}, {.03, .03}]];
x1 = a; y1 = 0; x2 = b; y2 = c; {XF, YF} = {x1 + x2, y1 + y2}/3;
CG = Graphics[Disk[{XF, YF}, {.05, .05}]];
Triang =
Graphics[Line[{{0, 0}, {a, 0}, {b, c}, {0, 0}, {XF, YF}, {a,
0}, {XF, YF}, {b, c}, {XF, YF}, {0, 0}}]];
bb = Show[{v1, v2, v3, Triang, CG}, GridLines -> Automatic,
Axes -> True, AspectRatio -> Automatic,
PlotLabel -> "Centre of Gravity"], {b, 0, 4}]

Have fun, Alexei

Alexei BOULBITCH, Dr., habil.
IEE S.A.
ZAE Weiergewan,
11, rue Edmond Reuter,
L-5326 Contern, LUXEMBOURG

Office phone :  +352-2454-2566
Office fax:       +352-2454-3566
mobile phone:  +49 151 52 40 66 44

e-mail: alexei.boulbitch at iee.lu

```

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