Re: 3DAspectRatio
- To: mathgroup at smc.vnet.net
- Subject: [mg131803] Re: 3DAspectRatio
- From: Bob Hanlon <hanlonr357 at gmail.com>
- Date: Tue, 8 Oct 2013 03:52:55 -0400 (EDT)
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- References: <20131007122401.C2A4C6A0F@smc.vnet.net>
a = 3; c = 5; ConPl = ContourPlot3D[ (Sqrt[x^2 + y^2] - c)^2 + z^2 == a^2, {x, -8, 8}, {y, -8, 8}, {z, -3.1, 3.1}, PlotRange -> {{-8, 8}, {-8, 8}, {-4, 4}}, BoxRatios -> {1, 1, 1/2}] ParPl = ParametricPlot3D[ {(a Cos[u] + c) Cos[v], (a Cos[u] + c) Sin[v], a Sin[u]}, {u, 0, 2 Pi}, {v, 0, 2 Pi}, PlotRange -> {{-8, 8}, {-8, 8}, {-4, 4}}, BoxRatios -> {1, 1, 1/2}] Sph = ParametricPlot3D[ {Cos[ph] Cos[t], Cos[ph] Sin[t], Sin[ph]}, {ph, -1.5, 1.5}, {t, 0, 2 Pi}, PlotRange -> {{-8, 8}, {-8, 8}, {-4, 4}}, BoxRatios -> {1, 1, 1/2}] Show[ParPl, ConPl, Sph, PlotRange -> {{-8, 8}, {-8, 8}, {-4, 4}}, BoxRatios -> {1, 1, 1/2}] Show[ConPl, ParPl, Sph, PlotRange -> {{-8, 8}, {-8, 8}, {-4, 4}}, BoxRatios -> {1, 1, 1/2}] Bob Hanlon On Mon, Oct 7, 2013 at 8:24 AM, Narasimham <mathma18 at gmail.com> wrote: > a=3; c=5; > ConPl=ContourPlot3D[ (Sqrt[x^2+y^2]- c)^2 + z^2 == a ^2 , > {x,-8,8},{y,-8,8},{z,-3.1,3.1}] > ParPl=ParametricPlot3D[{ (a Cos[u]+c) Cos[v], (a Cos[u]+c) Sin[v], a > Sin[u]},{u,0, 2Pi},{v,0, 2 Pi}] > Sph= ParametricPlot3D[1{ Cos[ph]Cos[t], Cos[ph] Sin[t], Sin[ph]}, > {ph,-1.5,1.5},{t,0, 2 Pi}] > Show[ParPl,ConPl,Sph] > Show[ConPl,ParPl,Sph] > > Is there some way to ContourPlot3D maintaining AspectRatio along all its > three axes? > > Regards > Narasimham > >
- References:
- 3DAspectRatio
- From: Narasimham <mathma18@gmail.com>
- 3DAspectRatio