Re: ReplacePart
- To: mathgroup at smc.vnet.net
- Subject: [mg131639] Re: ReplacePart
- From: Bob Hanlon <hanlonr357 at gmail.com>
- Date: Sun, 15 Sep 2013 07:06:06 -0400 (EDT)
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- References: <20130914100259.8EA2C6A1A@smc.vnet.net>
{5,10} is apparently interpreted as a position within an array rather than
a list of positions. Not sure why the algorithm isn't able to resolve the
ambiguity given that the input is a simple list. Or why there is no error
stating that position {5,10} does not exist.
x = {-1.25664, 0.628319, -0.628319, 1.25664, Indeterminate, -1.25664,
0.628319, -0.628319, 1.25664, Indeterminate};
x2 = x /. Indeterminate -> 0
{-1.25664, 0.628319, -0.628319, 1.25664, 0, -1.25664, 0.628319, -0.628319, \
1.25664, 0}
x2 ==
ReplacePart[x, {5 -> 0, 10 -> 0}] ==
ReplacePart[x, Thread[{5, 10} -> 0]] ==
ReplacePart[x, {{5} -> 0, {10} -> 0}] ==
ReplacePart[x, {{5}, {10}} -> 0] ==
ReplacePart[x, List /@ {5, 10} -> 0] ==
ReplacePart[x, Position[x, Indeterminate] -> 0]
True
Bob Hanlon
On Sat, Sep 14, 2013 at 6:02 AM, man21 <man21 at free.fr> wrote:
> Hello,
>
> As a result of a calculation, I end up with a list of numerical values
> which contains some "Indeterminate".
>
> x ={-1.25664, 0.628319, -0.628319, 1.25664, Indeterminate, -1.25664,
> 0.628319, -0.628319, 1.25664, Indeterminate}
>
> I try to replace the "Indeterminate" by "0", using :
>
> ReplacePart[x, {5, 10} -> 0.]
>
> but this dosen't work. Any idea why, and how to do it ?
>
> Thanks,
>
> Michel
>
>
>
- References:
- ReplacePart
- From: man21 <man21@free.fr>
- ReplacePart