Re: ReplacePart

*To*: mathgroup at smc.vnet.net*Subject*: [mg131644] Re: ReplacePart*From*: Itai Seggev <itais at wolfram.com>*Date*: Sun, 15 Sep 2013 07:07:47 -0400 (EDT)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-outx@smc.vnet.net*Delivered-to*: mathgroup-newsendx@smc.vnet.net*References*: <20130914100259.8EA2C6A1A@smc.vnet.net>

On Sat, Sep 14, 2013 at 06:02:59AM -0400, man21 wrote: > Hello, > > As a result of a calculation, I end up with a list of numerical values > which contains some "Indeterminate". > > x ={-1.25664, 0.628319, -0.628319, 1.25664, Indeterminate, -1.25664, > 0.628319, -0.628319, 1.25664, Indeterminate} > > I try to replace the "Indeterminate" by "0", using : > > ReplacePart[x, {5, 10} -> 0.] > > but this dosen't work. Any idea why, and how to do it ? A flat list in ReplacePart is interpreted as a single multi-level part specification. For example, In[282]:= ReplacePart[Array[a, {2, 2}], {1, 2} -> 0.] Out[282]= {{a[1, 1], 0.}, {a[2, 1], a[2, 2]}} What you want is this. In[280]:= ReplacePart[x, {{5}, {10}} -> 0.] Out[280]= {-1.25664, 0.628319, -0.628319, 1.25664, 0., -1.25664, \ 0.628319, -0.628319, 1.25664, 0.} I think in any event it is easier and better to use ReplaceAll In[283]:= x /. Indeterminate -> 0. Out[283]= {-1.25664, 0.628319, -0.628319, 1.25664, 0., -1.25664, \ 0.628319, -0.628319, 1.25664, 0.} -- Itai Seggev Mathematica Algorithms R&D 217-398-0700

**References**:**ReplacePart***From:*man21 <man21@free.fr>