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BitAnd[True,False]

  • To: mathgroup at smc.vnet.net
  • Subject: [mg131733] BitAnd[True,False]
  • From: Alan <alan.isaac at gmail.com>
  • Date: Wed, 25 Sep 2013 02:36:45 -0400 (EDT)
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I'd hoped BitAnd would work on Boolean Lists so I gave it a try.  If it had simply failed completely I'd be disappointed but would understand.  But oddly, it half succeeds.  Why? BitOr fails the same way, and BitNot always fails.

I just want to understand these results.  I know there are ways to get the output I want.

Thanks,
Alan Isaac
(using Mathematica 9)

In[77]:= BooleanTable[{p,q,BitAnd[p,q]},{p,q}]//TableForm
Out[77]//TableForm= 
True	True	True
True	False	BitAnd[False,True]
False	True	BitAnd[False,True]
False	False	False




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