Re: a simple question
- To: mathgroup at smc.vnet.net
- Subject: [mg131734] Re: a simple question
- From: "Barrie Stokes" <Barrie.Stokes at newcastle.edu.au>
- Date: Wed, 25 Sep 2013 02:37:06 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-outx@smc.vnet.net
- Delivered-to: mathgroup-newsendx@smc.vnet.net
- References: <20130924015950.56E2A6A52@smc.vnet.net>
Hi Murray
A neat and simple answer to a simple question, and as always with yourself and a few other MathGroup regulars, very helpful.
I can't help feeling, though, every time I see a question of this type ("I am beginner for Mathematica"), that the poster has not even tried to look into the Help.
In real life when I'm asked a question like this, my first response is usually to say, "Show me what you've tried."
Or else I would be tempted to answer, somewhat in the Bob Hanlon style, "See http://reference.wolfram.com/mathematica/ref/Solve.html";.
As I've said more than once before in a similar MathGroup gripe, "Give a man a fish, feed him for a day; teach a man to fish, feed him for a lifetime". (Lao Tzu, apparently.)
Best wishes
Barrie
>>> Murray Eisenberg <murray at math.umass.edu> 09/24/13 6:17 PM >>>
Do you mean you want to solve that equation for h? (That's a different thing than "evaluating it", which would not be possible since the left hand side is not the sort of expression to which you can assign a value -- and what does is to assign a value. Whereas == denotes an equality.)
Perhaps you mean something like the following:
Solve[A Log[h]/h - x == 0, h]
The result you'll get gives the solution as:
h -> -((A*ProductLog[-(x/A)])/x
This may or may not be of use to you, since ProductLog is a not an "elementary" function.
Do A and x have some specific values?
By the way, it's a bad idea to use names in Mathematica that are, or begin with, an upper-case letter -- because that risks confounding them with the names of built-in objects.
On Sep 23, 2013, at 9:59 PM, Dhaneshwar Mishra <dhaneshwarmishra at gmail.com> wrote:
>
> I would like to evaluate A*Log[h]/h -x=0 for h, can any body help me doing so?
>
> I am beginner for Mathematica.
---
Murray Eisenberg
murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower
University of Massachusetts
710 North Pleasant Street
Amherst, MA 01003-9305
- References:
- a simple question
- From: Dhaneshwar Mishra <dhaneshwarmishra@gmail.com>
- a simple question