Re: For 2014?

*To*: mathgroup at smc.vnet.net*Subject*: [mg132151] Re: For 2014?*From*: Dana DeLouis <dana01 at icloud.com>*Date*: Fri, 3 Jan 2014 04:43:27 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-outx@smc.vnet.net*Delivered-to*: mathgroup-newsendx@smc.vnet.net

> .. There are some nice (very simple) math puzzles using consecutive integers that produce years. For example, 10+(9 x 8 x (7/6) x 5 x 4)+321 Hi. For an interesting article, see the blog titled Happy 10*9*8+7+6-5+4*321 ! http://blog.wolfram.com/2012/02/02/happy-109876-54321/ ~Dana DeLouis Harvey P. Dale =09 Dec 24 There are some nice (very simple) math puzzles using consecutive integers that produce years. For example, 10+(9 x 8 x (7/6) x 5 x 4)+321 and 0-12+(34 x 56)+7 x (8+9) both yield 2011, and (10 x 9 x 8) + 7 + 6 - 5 + (4 x 321) yields 2012. Two questions: (1) can anyone generate a similar puzzle yielding 2014 and (2) is there a general Mathematica program that can generate these? Best, Harvey