Re: For 2014?

*To*: mathgroup at smc.vnet.net*Subject*: [mg132152] Re: For 2014?*From*: Ulrich Arndt <ulrich.arndt at data2knowledge.de>*Date*: Fri, 3 Jan 2014 04:43:47 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-outx@smc.vnet.net*Delivered-to*: mathgroup-newsendx@smc.vnet.net*References*: <20131224071749.C3F1A69D5@smc.vnet.net> <3688DC0E-CE14-47F1-B93B-5BFA875C59E3@data2knowledge.de> <20131226112449.4994F6A09@smc.vnet.net> <644455E9-F8F1-491C-9EFE-1198A90B8FED@wolfram.com>

Thanks for sharing. Was obviously not aware of this. Here a tweet conform code e.g. 139 chars - output could be nicer but 140 is a strong limitation given the long function names... l=Range[9];r=StringJoin[Riffle[ToString/@l,#]]&/@Tuples[{"+","-","*","/",""},8];Grid[{#,Extract[r,Position[ToExpression/@r,#]]}&/@(l+2010)] Ulrich Am 28.12.2013 um 23:45 schrieb carlson at wolfram.com: > I wrote a blog post about this a while ago which has a downloadable notebook with code. There's also a reference to a post by Hans Havermann on the same topic. > > http://blog.wolfram.com/2012/02/02/happy-109876-54321/ > > Chris > > > On Dec 26, 2013, at 5:24 AM, Ulrich Arndt <ulrich.arndt at data2knowledge.de> wrote: > >> Actually it has to be SeedRandom[1992] - was late ;-). >> >> But also an complete check is possible - and therefore much better... >> >> char = CharacterRange["1", "9"] >> type = {"+", "-", "*", "/", ""} >> >> t = Tuples[type, 8]; >> r = StringJoin[Riffle[char, #]] & /@ t; >> e = ToExpression[#] & /@ r; >> p = Position[e, 2014] >> Extract[r, p] >> >> Works also for reversed number list. >> >> Ulrich >> >> Am 24.12.2013 um 22:05 schrieb Ulrich Arndt: >> >>> 123 + 45*6*7 - 8 + 9 >>> >>> Generate is maybe a bit wrong - search ;-) >>> >>> char = CharacterRange["1", "9"] >>> type = {"+", "-", "*", "/", ""} >>> RandomSeed[1992] >>> r = Table[StringJoin[Riffle[char, RandomChoice[type, 8]]], {1000000}]; >>> e = ToExpression[#] & /@ r; >>> p = Position[e, 2014] >>> Union[Extract[r, p]] >>> >>> 2015 >>> 1*2-3+4*567*8/9, 12*3+45*6*7+89, 12*34*5-6*7+8+9 >>> >>> >>> >>> >>> >>> >>> Am 24.12.2013 um 08:17 schrieb Harvey P. Dale: >>> >>>> There are some nice (very simple) math puzzles using consecutive integers that produce years. For example, 10+(9 x 8 x (7/6) x 5 x 4)+321 and 0-12+(34 x 56)+7 x (8+9) both yield 2011, and (10 x 9 x 8) + 7 + 6 - 5 + (4 x 321) yields 2012. >>>> >>>> Two questions: (1) can anyone generate a similar puzzle yielding 2014 and (2) is there a general Mathematica program that can generate these? >>>> >>>> Best, >>>> >>>> Harvey >>>> >>> >>> >> >> >> >