Re: For 2014?
- To: mathgroup at smc.vnet.net
- Subject: [mg132192] Re: For 2014?
- From: Ulrich Arndt <ulrich.arndt at data2knowledge.de>
- Date: Mon, 13 Jan 2014 02:24:05 -0500 (EST)
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- References: <20131224071749.C3F1A69D5@smc.vnet.net> <3688DC0E-CE14-47F1-B93B-5BFA875C59E3@data2knowledge.de> <20131226112449.4994F6A09@smc.vnet.net> <644455E9-F8F1-491C-9EFE-1198A90B8FED@wolfram.com> <la606o$faj$1@smc.vnet.net> <20140107075437.D0DF569ED@smc.vnet.net> <lao80v$pmm$1@smc.vnet.net> <20140112073203.5EAE569D4@smc.vnet.net>
Hahaha, it's sometimes to easy to fool yourself ;-). I was always reading this in a way that it will be done only once as it the same for all calls... Thanks Ulrich Am 12.01.2014 um 08:32 schrieb Bogu=C5=9B: > Ulrich Arndt wrote: >> Yes, this is much faster - 5 times on my machine. >> Problem is that we get 141 chars even if we replace the re by b ;-). >> >> But can someone explain the reason for the huge processing time difference? >> >> Ulrich >> > > > = l=Range[9];r=StringJoin[Riffle[ToString/@l,#]]&/@Tuples[{"+","-","*","/",""},8];Grid[{#,Extract[r,Position[ToExpression/@r,#]]}&/@(l+2010)] > > Position[ToExpression/@r,#] > ^^^^^ This is the slowest process. 9 times repeated > > -- > Costa >
- References:
- Re: For 2014?
- From: Costa Bravo <q13a27tt@aol.com>
- Re: For 2014?
- From: Boguś <telemorele@wp.pl>
- Re: For 2014?