RE: Re: Assigning solutions fou
- To: mathgroup at smc.vnet.net
- Subject: [mg9490] RE: [mg9450] Re: Assigning solutions fou
- From: Ersek_Ted%PAX1A at mr.nawcad.navy.mil
- Date: Sat, 8 Nov 1997 23:04:23 -0500
- Sender: owner-wri-mathgroup at wolfram.com
Hein Hundal replied to a question about how to convert a list of Rules
from FindRoot to a list of numbers.
Hein said:
|
| Try
|
| sols=FindRoot[{x == y, x + y == 2}, {x, 0}, {y, 0}] Set @@#& /@ sols |
|
Are you sure? It doesn't work for me unless I include a semi-colon as
follows:
In[1]:= sols=FindRoot[{x == y, x + y == 2}, {x, 0}, {y, 0}] ;Set @@#&
/@ sols
Out[1]= {1.,1.}
I find this sort of code very cryptic, and I think it's a sure fire way
to turn off beginners.
Besides that it goes about the task in a round about way. Something like
the following is more direct and more readable.
In[2]:= solution=FindRoot[{x == y, x + y == 2}, {x, 0}, {y, 0}]
Out[2]= {1.\[Rule]1.,1.\[Rule]1.}
In[3]:= {x,y}/.solution
Out[3]= {1.,1.}
Note: I didn't put a semi-colon after FindRoot[.......] so a beginner
will know what the next line is working on. Now if the user wanted to
assign values to {x,y} they could use the following.
In[4]:= {x,y}={x,y}/.solution
Out[4]= {1.,1.}
Ted Ersek
ersek_ted%pax1a at mr.nawcad.navy.mil