Re: Re: How do u go about doing this---?
- To: mathgroup@smc.vnet.net
- Subject: [mg10957] Re: [mg10932] Re: [mg10844] How do u go about doing this---?
- From: jpk@max.mpae.gwdg.de
- Date: Sat, 14 Feb 1998 00:53:27 -0500
Yes, Sorry, Thanks
Jens
> Oops Jens,
> you overlooked the fact that he wanted the sum of squares of the first
> derivative, not the sum of the second derivatives.
> Happens to the best of us, at least some of the time. I goof myself now &
> then, I know the feeling. But *do* go on replying. The least we, non-guru's,
> can do is relieve some of the workload of the "Abbotts & Hintons", letting
> them treat the stuff we can't.
>
> with sympathy
>
> wouter.
>
> >> Show that
> >> (df/dx)^2 + (df/dy)^2 =
> >Hi, it can't be shown because with
> >f[x,y]->(Sin[x]+Cos[y])/(Sin[x]-Cos[y])
> >
> >one gets for
> >
> >D[f[x,y],{x,2}]+D[f[x,y],{y,2}]=
> >
> >(-4*(Cos[x]^2*Cos[y] + Sin[x]*Sin[y]^2))/(Cos[y] - Sin[x])^3
> >
> >what is clearly different from Your "result"
> >
> >Hope that helps
> > Jens
> >
> >
>
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