       Re: How do I solve limits in Mathematica?

• To: mathgroup at smc.vnet.net
• Subject: [mg17126] Re: [mg17053] How do I solve limits in Mathematica?
• From: "Tomas Garza" <tgarza at mail.internet.com.mx>
• Date: Sat, 17 Apr 1999 03:35:16 -0400
• Sender: owner-wri-mathgroup at wolfram.com

```Jeffrey A. Soesbergen [Voyager_2 at cable.A2000.nl] wrote:

> How can I solve the following expressions in Mathematica? Anyone?
>
> 1)
>
> lim (2x-1) == -1
> (x->0)
>
> 2)
>
> lim (2x^2+1) == 3
> (x->1)
>
> I can't figure out how to solve those expressions, so if anyone
> can tell me...

Jeffrey,

What do you mean, "solve"? Either you want to evaluate the limits, or you
want to test if the expression lhs == rhs is true or false.

In:=
Limit [2x-1,x->0]

Out=
-1

In:=
Limit [2x-1,x->0]==-1

Out=
True

In:=
Limit[2x^2+1,x->1]

Out=
3

In:=
Limit[2x^2+1,x->1]==3

Out=
True

Tomas Garza
Mexico City

```

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