Re: How do I solve limits in Mathematica?

• To: mathgroup at smc.vnet.net
• Subject: [mg17074] Re: How do I solve limits in Mathematica?
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Sat, 17 Apr 1999 03:34:48 -0400
• Organization: Universitaet Leipzig
• References: <7f1esn\$krh@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Hi Jeffrey,

what do you want to solve ?

Limit[2 x-1,x->0]  is equal to -1 so will only get -1 == -1 and that is
evaluated to True. There is no variable for what you can solve your
equation and

Solve[Limit[2x+y-1,x->0]==-1,y]

works fine

Regards
Jens

"Jeffrey A. Soesbergen" wrote:
>
> How can I solve the following expressions in Mathematica? Anyone?
>
> 1)
>
> lim (2x-1) == -1
> (x->0)
>
> 2)
>
> lim (2x^2+1) == 3
> (x->1)
>
> I can't figure out how to solve those expressions, so if anyone can tell me...
> thanks !
>
> J.

```

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