Re: How do I solve limits in Mathematica?
- To: mathgroup at smc.vnet.net
- Subject: [mg17074] Re: How do I solve limits in Mathematica?
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Sat, 17 Apr 1999 03:34:48 -0400
- Organization: Universitaet Leipzig
- References: <email@example.com>
- Sender: owner-wri-mathgroup at wolfram.com
Hi Jeffrey, what do you want to solve ? Limit[2 x-1,x->0] is equal to -1 so will only get -1 == -1 and that is evaluated to True. There is no variable for what you can solve your equation and Solve[Limit[2x+y-1,x->0]==-1,y] works fine Regards Jens "Jeffrey A. Soesbergen" wrote: > > How can I solve the following expressions in Mathematica? Anyone? > > 1) > > lim (2x-1) == -1 > (x->0) > > 2) > > lim (2x^2+1) == 3 > (x->1) > > I can't figure out how to solve those expressions, so if anyone can tell me... > thanks ! > > J.