Re: Replacing Part of a Matrix
- To: mathgroup at smc.vnet.net
- Subject: [mg20273] Re: [mg20250] Replacing Part of a Matrix
- From: "David Park" <djmp at earthlink.net>
- Date: Sun, 10 Oct 1999 01:27:29 -0400
- Sender: owner-wri-mathgroup at wolfram.com
Wilson,
Here is one routine. You may get others more elegant.
ReplaceCenter[(a_)?MatrixQ, (b_)?MatrixQ] /;
Dimensions[a] == ({n, m} = Dimensions[b]) + 2 :=
Module[{c = a}, Do[c[[i + 1,j + 1]] = b[[i,j]],
{i, n}, {j, m}]; c]
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
>Hello all,
>
>I have a n x n matrix, call it A.
>
>I have a (n - 2)x(n - 2) matrix, call it B.
>
>I would like to keep the outer rows and columns
>of A, but repalce the inner rows and columns with
>thos of B to get a new C.
>
>I looked at the ReplacePart and other matrix and
>list manipulation rules and couldn't quite find
>one.
>
>I wrote a very gross module to do it.
>
>Does anyone have such a module in Mathematica they would
>like to share.
>
>For example,
>
>c = replace_a_b[a, b]
>
>would return the desired result.
>
>Example:
>
>A = {{1,2,3,4},{5,6,7,8},{9,10,11,12},
>{13,14,15,16}}
>B = {{20,30,},{40,50}}
>
>C = replace_a_b[A,B], would produce:
>
>C = {{1,2,3,4},{5,20,30,8},{9,40,50,12},
>{13,14,15,16}}
>
>Basically, this function just replaces the
>interior (n-2)x(n-2) in the larger matrix.
>
>Can anyone help?
>
>By the way, thank you to all who responded with
>such an easy and useful rectangular grid
>generator.
>
>Thank you.
>
>Wilson Figueroa
>flip at safebunch.com
>http://safebunch.com
>
>
>Sent via Deja.com http://www.deja.com/
>Before you buy.
>
>