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Re: Initializing subscripted variables

  • To: mathgroup at
  • Subject: [mg24910] Re: [mg24879] Initializing subscripted variables
  • From: BobHanlon at
  • Date: Sun, 20 Aug 2000 01:34:58 -0400 (EDT)
  • Sender: owner-wri-mathgroup at

In a message dated 8/19/2000 5:06:23 AM, hpd1 at writes:

>   I want to define a function recursively, and must initialize the
>value of the first few instances.  For example:
>   f[1]=f[2]=f[3]=f[4]=1; f[n_]:=f[n-1]+f[n-2]+f[n-3]-f[n-4]
>Here's the question: is there a way to write a function, e.g., a Table,
>will generate the code preceding the semicolon above?
>   It is easy to generate a list of f[1], f[2], . . ., f[n], by
>Threading f across the Range of desired initial subscripted variables.
> My
>problem is how to join the listed initial subscripted variables with a
>single equals sign.  (It is fairly easy to get the Boolean double-equals
>sign between them, but I've discovered no way to get the single equals

Pick one

(f[#] = 1) & /@ Range[4];

Table[f[n] = 1, {n, 4}];

(# = 1) & /@ Table[f[n], {n, 4}];

Evaluate[Table[f[n], {n, 4}]] = Table[1, {4}];

Bob Hanlon

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