Re: Integrate doesn't yield what I expect
- To: mathgroup at smc.vnet.net
- Subject: [mg25394] Re: Integrate doesn't yield what I expect
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Fri, 29 Sep 2000 01:06:27 -0400 (EDT)
- Organization: Universitaet Leipzig
- References: <8qloab$q7g@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi,
you expect AcrSin[] and get Log[] - unfortunatly there isn't a solution
for it because every inverse trigonometric function has an logarithmic
representation ;-)
ArcSin[x] -> -I*Log[Sqrt[(1-x^2)]+I*x] x^2<=1
because Sin[x]=Exp[I*x]-Exp[-I*x]/(2I)
You should look at the equations 4.4.26 -- 4.4.31 in Abramowitz/Stegun
> Can you also guide me to the best book with solved integrals? (best means
> number of integrals solved)
I. S. Granstein, I. M. Ryshik
"Table of Series, Products and Integrals"
Regards
Jens
Gransteint
Borut L wrote:
>
> Helo,
>
> I am integrating a function which has the form
> 1/(x Sqrt[a x^2+b x+c]),
> where c<0 and delta=4 a c-b^2 <0.
> Matematica always returns same result (with Log, the one with delta>0),
> despite giving option Assumptions->{...}. I expect a result with ArcSin. Is
> there other way to treat such somplex integrals?
>
> In my real assignemt I have an integral 1/(x^2 (a x^2+b x+c)^(3/2)) with
> same c and delta. I expect again something with ArcSin or ArcCos, but the
> Log is again yilded.
>
> Can you also guide me to the best book with solved integrals? (best means
> number of integrals solved)
>
> Thanks, Borut