       Re: A New User

• To: mathgroup at smc.vnet.net
• Subject: [mg29377] Re: A New User
• From: "Jim-dars" <jim-dars at mediaone.net>
• Date: Sat, 16 Jun 2001 02:47:50 -0400 (EDT)
• References: <9g74cq\$cg1\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Hi All,

Thank you all for your suggestions.  For someone just beginning, the
"Simplify" was what I needed.  The "Coefficient" was grand, it only required
I use "IntegerFactor" in advance so I'd know what Mathematica would "use"
for c.

Thanks again, best wishes, Jim

"Jim-dars" <jim-dars at mediaone.net> wrote in message
news:9g74cq\$cg1\$1 at smc.vnet.net...
> Hi All,
>
> I have a problem of the form:
>
>       (2+Sqrt(3))*(1+2*Sqrt(3))
>
> I would like Mathematica to present the solution in the form (8 +
> 5*Sqrt(3)).
>
> Of course, I realize I can calculate the two components.  However, since
> this situation occurs repeatedly in a problem I'm solving, it would be
very
> convenient to have Mathematica display the answer directly.  In fact, if
> Mathematica could provide me with a=8 and b=5 that would be even better.
>
> My actual problem is of the form:
>
>          (a+b*Sqrt(c))*(d+e*Sqrt(c))^k  = (f+g*Sqrt(c))
>
> where a,b,c,d, and e are positive integers.  c is not a perfect square,
but
> may contain a square factor.
> k is an integer such that -infinity < k < infinity.   It is desired to
find
> f and g.  (Actually, just g.)
>
> Best wishes, Jim
>
>

```

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