Re: A New User
- To: mathgroup at smc.vnet.net
- Subject: [mg29377] Re: A New User
- From: "Jim-dars" <jim-dars at mediaone.net>
- Date: Sat, 16 Jun 2001 02:47:50 -0400 (EDT)
- References: <9g74cq$cg1$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi All, Thank you all for your suggestions. For someone just beginning, the "Simplify" was what I needed. The "Coefficient" was grand, it only required I use "IntegerFactor" in advance so I'd know what Mathematica would "use" for c. Thanks again, best wishes, Jim "Jim-dars" <jim-dars at mediaone.net> wrote in message news:9g74cq$cg1$1 at smc.vnet.net... > Hi All, > > I have a problem of the form: > > (2+Sqrt(3))*(1+2*Sqrt(3)) > > I would like Mathematica to present the solution in the form (8 + > 5*Sqrt(3)). > > Of course, I realize I can calculate the two components. However, since > this situation occurs repeatedly in a problem I'm solving, it would be very > convenient to have Mathematica display the answer directly. In fact, if > Mathematica could provide me with a=8 and b=5 that would be even better. > > My actual problem is of the form: > > (a+b*Sqrt(c))*(d+e*Sqrt(c))^k = (f+g*Sqrt(c)) > > where a,b,c,d, and e are positive integers. c is not a perfect square, but > may contain a square factor. > k is an integer such that -infinity < k < infinity. It is desired to find > f and g. (Actually, just g.) > > Best wishes, Jim > >