Exponential Equations
- To: mathgroup at smc.vnet.net
- Subject: [mg29611] Exponential Equations
- From: "Shippee, Steve" <SHIS235 at LNI.WA.GOV>
- Date: Thu, 28 Jun 2001 05:28:01 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
If this is too basic of a question for the "LIST", please respond to me
directly via email at shippee at jcs.mil and thanks in advance for any
assistance provided. I'd be happy to provide you a "notebook", too, if that
would help.
With the equation e^5x = 1/e^2x + 7 [e is the mathematical e = 2.718]
If I use Solve[e^5x == 1/e^2x + 7] I do not get an appropriately traditional
answer. The RHS of the equation is the mathematical "e" to the power of 2x
+ 7.
Using the equation e^5x = 1/e^2x + 7 It appears to me Mathematica is
skipping the step
e^5x = e^-(2x + 7 )
which would result in
5x = -(2x + 7)
5x = -2x - 7
7x = -7
x = -1
Because with Mathematica I kept getting the answer:
Out[1]= \!\({{x \[Rule] Log[Root[\(-1\) + 7\ #1\^5 + #1\^7 &, 1]]}, {x
\[Rule] Log[Root[\(-1\) + 7\ #1\^5 + #1\^7 &, 2]]}, {x \[Rule]
Log[Root[\(-1\) + 7\ #1\^5 + #1\^7 &, 3]]}, {x \[Rule] Log[Root[\(-1\) + 7\
#1\^5 + #1\^7 &, 4]]}, {x \[Rule] Log[Root[\(-1\) + 7\ #1\^5 + #1\^7 &,
5]]}, {x \[Rule] Log[Root[\(-1\) + 7\ #1\^5 + #1\^7 &, 6]]}, {x \[Rule]
Log[Root[\(-1\) + 7\ #1\^5 + #1\^7 &, 7]]}}\)
Before trying all of the above, I loaded:
<< Graphics`Graphics`
<< Algebra`AlgebraicInequalities`
<< Algebra`InequalitySolve`
<< Algebra`RootIsolation`
- Follow-Ups:
- Re: Exponential Equations
- From: Tomas Garza <tgarza01@prodigy.net.mx>
- Re: Exponential Equations