Re: Handling a list: Could you find a more elegant solution?
- To: mathgroup at smc.vnet.net
- Subject: [mg38238] Re: Handling a list: Could you find a more elegant solution?
- From: kzhang at flashmail.com (Kezhao Zhang)
- Date: Tue, 10 Dec 2002 04:09:31 -0500 (EST)
- References: <asn36u$40k$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Use ListCorrelate:
In[1]:=ListCorrelate[{1, 1}, {a, b, c, d, e}]/2
a + b b + c c + d d + e
Out[1]= {-----, -----, -----, -----}
2 2 2 2
Kezhao
guillerm at usal.es wrote in message news:<asn36u$40k$1 at smc.vnet.net>...
> I have a list:
>
> list1 = {a, b, c, d, e};
>
> I want manipulate the list to obtain:
>
> (*Out[]:{(a + b)/2, (b + c)/2, (c + d)/2, (d + e)/2}*)
>
> It can be done for this function
>
> f[data_List] := Drop[Plus @@ NestList[RotateRight, data,
> 1], 1]/2
>
> f[list1]
>
> but I am sure that some member of the group can find a more elegant function. I
> will appreciate to know it.
>
> Thanks
>
> Guillermo Sanchez
>
>
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