Re: Integrate Problem
- To: mathgroup at smc.vnet.net
- Subject: [mg40514] Re: Integrate Problem
- From: bobhanlon at aol.com (Bob Hanlon)
- Date: Wed, 9 Apr 2003 01:30:19 -0400 (EDT)
- References: <b6tsvb$n20$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
$Version
4.2 for Mac OS X (August 22, 2002)
Simplify[Integrate[1/Pi^2 1/(1+x^2+y^2+z^2)^2,{z,-Infinity,Infinity}],
Element[{x,y}, Reals]]
1/(2*Pi*(1 + x^2 + y^2)^(3/2))
Bob Hanlon
In article <b6tsvb$n20$1 at smc.vnet.net>, Stewart Mandell <stewart at rentec.com>
wrote:
<<
Subject: Integrate Problem
From: Stewart Mandell <stewart at rentec.com>
To: mathgroup at smc.vnet.net
Date: Tue, 8 Apr 2003 07:15:55 +0000 (UTC)
When I run
Integrate[1/Pi^2 1/(1 + x^2 + y^2 + z^2)^2, {z, -Infinity, Infinity},
Assumptions -> {Im[x] == 0, Im[y] == 0, Im[z] == 0}]
I get
(I*(Log[-(I/Sqrt[1 + x^2 + y^2])] -
Log[I/Sqrt[1 + x^2 + y^2]]))/
(2*Pi^2*(1 + x^2 + y^2)^(3/2))
I would like
1/(2*Pi ) 1/(1 + x^2 + y^2)^3/2
for an answer. How do I get Mathematica to forego the complex
answer?
thanks, Stewart
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