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Re: Problem

  • To: mathgroup at smc.vnet.net
  • Subject: [mg43031] Re: [mg42967] Problem
  • From: Janak Wedagedera <janak at maths.warwick.ac.uk>
  • Date: Sat, 9 Aug 2003 02:57:33 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Hello,
You can use ImpliciPlot:

<< Graphics`ImplicitPlot`
ImplicitPlot[(x - x^2) + (y - y^2) == c, {x, a, b}]

Case c=0 is straightforward, but need to specify
the corresponding range for c for the real solutions of y.

Eg:
ImplicitPlot[(x - x^2) + (y - y^2) == -1, {x, -1, 1}]

(c=-1).

Is this what you need; sorry if I am wrong.

Best regards

janak.

On Thu, 7 Aug 2003, Andrew Thomas wrote:

> Dear All,
>
> This is a simple one but I cannot find out how to plot the following.
>
> c=(x-x^2)+(y-y^2) where c is a constant.
>
> The problem is that everytime I go to plot the plot is always defined
> as y=f(x,...) and so I cannot enter y^2 into the equation.
>
> Could someone please advise.
>
> Thank you and best wishes,
>
> Andrew
>
>
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------------------------------------
Dr. Janak R Wedagedera
Research Fellow
Mathematics Institute
University of Warwick
Coventry
CV4 7AL
U.K.

e-mail: janak at maths.warwick.ac.uk
	janak at maths.ruh.ac.lk

phone: 44 02476 523698 (office)
------------------------------------


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