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Re: graphs and AxesOrigin

  • To: mathgroup at smc.vnet.net
  • Subject: [mg43095] Re: graphs and AxesOrigin
  • From: bobhanlon at aol.com (Bob Hanlon)
  • Date: Tue, 12 Aug 2003 04:43:08 -0400 (EDT)
  • References: <bh7d77$54n$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

c=0.5;
M=1000;
k1=950;
d=0.52;
k2=750;
p2=(1-c)*((M-d*(M-k2))/(2*(1-d)*k1))+c;
S1=(1-c)*((1-d)*k1+d*(M-k2));
L1=(1-c)*(((1-d)*(p2-c)*k1+d*(1-c)*(M-k2))/(1-c));
U1=(1-c)*(d*k1+(1-d)*(M-k2));
f[v_]:=Min[(1-c)*M-v,
      ((v-d*(1-c)*(M-k2))/
            ((1-d)*k1))*(M-v/(1-c))];

Plot[f[v],{v,L1,U1},
    PlotStyle->RGBColor[0,0,1],
    AxesOrigin->{L1,f[U1]}];

You might want to check your definition for L1.  As is, you appear to multiply
and divide by (1-c).


Bob Hanlon

In article <bh7d77$54n$1 at smc.vnet.net>, Emmanuel Dechenaux
<dechenau at purdue.edu> wrote:

<< I have what I assume is a simple question. I'm trying to make the graph 
below but if I let mathemtica determine the origin it puts the vertical 
axis in the middle of the curve. I don't want this to happen, so I use 
AxesOrigin. Now unfortunately it doesn't show the axes all the way to 
the origin, it doesn't go beyong the range I specified for the variable 
in the function I want to plot. I was wondering if there's a way for 
this not to happen (the plot range can't possibly be different). Thanks.
Emmanuel

\!\(c = 0.5\[IndentingNewLine]
  M = 1000\[IndentingNewLine]
  k1 = 950\[IndentingNewLine]
  d = 0.52\[IndentingNewLine]
  k2 = 750\[IndentingNewLine]
  p2 = \((1 - c)\) \(M - d \((M - k2)\)\)\/\(2 \((1 - d)\) k1\) +
      c\[IndentingNewLine]
  S1 = \((1 - c)\) \((\((1 - d)\) k1 + d \((M - k2)\))\)\[IndentingNewLine]
  L1 = \((1 -
          c)\) \((\(\((1 - d)\) \((p2 - c)\) k1 + d \((1 - c)\) \((M - \
k2)\)\)\/\(1 - c\))\)\[IndentingNewLine]
  U1 = \((1 -
          c)\) \((d \((k1)\) + \((1 - d)\) \((M - 
k2)\))\)\[IndentingNewLine]
  Plot[Min[\((1 - c)\) M -
        v, \((\(v - d \((1 - c)\) \((M - k2)\)\)\/\(\((1 - d)\) k1\))\) 
\((M \
- v\/\((1 - c)\))\)], {v, L1, U1}]\)


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