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Re: Lines in ContourPlot

  • To: mathgroup at smc.vnet.net
  • Subject: [mg41757] Re: Lines in ContourPlot
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Wed, 4 Jun 2003 08:34:40 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <bb73h3$b7s$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,


Solve[a(a - 1)(a - 2) - 2b(b - 1)(b - 2) == 0, b] // FullSimplify

or graphical:

line = Cases[
      Graphics[ContourPlot[
          a(a - 1)(a - 2) - 2b(b - 1)(b - 2), {a, 2, 20}, {b, 2, 20}, 
          PlotPoints -> 100, Contours -> {0}, 
          DisplayFunction -> Identity]], _Line, Infinity];

??

Regards
  Jens

Friedrich Laher wrote:
> 
> would it be possible to get a "line" for the zerovalues in the following?
> ContourPlot[a(a - 1)(a - 2) - 2b(b - 1)(b - 2), {a, 2, 20}, {b, 2, 20},
>    PlotPoints -> 100]


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