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AW: Re: SOLVING A CUBE

  • To: mathgroup at smc.vnet.net
  • Subject: [mg48909] AW: [mg48882] Re: SOLVING A CUBE
  • From: Matthias.Bode at oppenheim.de
  • Date: Wed, 23 Jun 2004 02:51:01 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Hi Stergios,

you only calculated the four "columns" inside the cube. The remaining
"walls" will yield 24 additional pieces. Apply your method thrice.

Best regards,
Matthias Bode
Sal. Oppenheim jr. & Cie. KGaA
Untermainanlage 1
D-60329 Frankfurt am Main
GERMANY 
Tel.: +49(0)69 71 34 53 80
Mobile: +49(0)172 6 74 95 77
Fax: +49(0)69 71 34 95 380
E-mail: matthias.bode at oppenheim.de
Internet: http://www.oppenheim.de



-----Ursprüngliche Nachricht-----
Von: Stergios J. Papadakis [mailto:stergios.papadakis at jhuapl.edu] 
Gesendet: Dienstag, 22. Juni 2004 11:31
An: mathgroup at smc.vnet.net
Betreff: [mg48882] Re: SOLVING A CUBE


Alexey Semenov wrote:

> Hi everyone.
> 
> I would greatly appreciate if you can help me with a link to a modeling
> software program or a formula for calculating the following:
> 
> I have piece of rock which equals to 1 cubic meter (length/height/width-
one
> meter each side). I need to cut pieces that equal to 45cm X 45cm X 3cm
> (length/width/height). How many of these pieces i can get out of a 1 cubic
> meter stone?

Am I missing something or is it just
IntegerPart[L/l]*IntegerPart[W/w]*IntegerPart[H/h]?

Stergios


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