MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Eliminating parameters

  • To: mathgroup at smc.vnet.net
  • Subject: [mg61602] Re: Eliminating parameters
  • From: Bill Rowe <readnewsciv at earthlink.net>
  • Date: Sun, 23 Oct 2005 05:46:11 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

On 10/22/05 at 12:36 AM, pacoga at ctv.es (Francisco Javier) wrote:

>Suppose that {X, Y, Z} = {f[u,v], g[u,v], h[u, v]} and that we want
>to eliminate u, v and get an equation in X, Y, Z.

>Then we can try

>Eliminate[{X-f[u,v], Y-g[u,v], Z-h[u,v]},{u, v}]

>This time f, g, w contain square roots and I think that this is the
>reason by which Eliminate seems don't work (after 15 minutes I
>aborted the calculation)

>Is there any enhancement or substitute for Eliminate in this case?

Quite possibly, there is a way to solve your problem in reasonable time. But you have not provided enough detail for anyone to propose a solution. You need provided the code that defines f,g and h.

And if you are literally doing

In[1]:={X, Y, Z} = {f[u, v], g[u, v], h[u, v]}
Out[1]={f[u, v], g[u, v], h[u, v]}

In[2]:={X - f[u, v], Y - g[u, v], Z - h[u, v]}
Out[2]={0, 0, 0}

It should be obvious why Mathematica cannot solve the problem
--
To reply via email subtract one hundred and four


  • Prev by Date: Re: Language vs. Library why it matters
  • Next by Date: Re: incompatible standard packages
  • Previous by thread: Re: Eliminating parameters
  • Next by thread: incompatible standard packages