RE: A problem in calculus
- To: mathgroup at smc.vnet.net
- Subject: [mg72481] RE: [mg72469] A problem in calculus
- From: "David Park" <djmp at earthlink.net>
- Date: Sun, 31 Dec 2006 05:35:07 -0500 (EST)
j would have to be a positive integer.
x[z_] := a4*z^4 + a3*z^3 + a2*z^2 + a1*z + 1
For the 3rd derivative, say, use
D[Sqrt[x[z]], {z, 3}]
(3*(a1 + 2*a2*z + 3*a3*z^2 + 4*a4*z^3)^3)/
(8*(1 + a1*z + a2*z^2 + a3*z^3 + a4*z^4)^(5/2)) -
(3*(2*a2 + 6*a3*z + 12*a4*z^2)*(a1 + 2*a2*z +
3*a3*z^2 + 4*a4*z^3))/
(4*(1 + a1*z + a2*z^2 + a3*z^3 + a4*z^4)^(3/2)) +
(6*a3 + 24*a4*z)/(2*Sqrt[1 + a1*z + a2*z^2 +
a3*z^3 + a4*z^4])
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
From: kaipku at gmail.com [mailto:kaipku at gmail.com]
Hi
I have a problem to solve.
Let x(z)= a4*z^4+a3*z^3+a2*z^2+a1*z+1 be a polynomial in z.
I want the formula of the j'th derivative in z of (x(z))^(1/2). I think
this kind of problems should have been solved. But I do not
know where to find the formula. Could someone please find it for
me? Thank you very much!