Re: simple antiderivative
- To: mathgroup at smc.vnet.net
- Subject: [mg68123] Re: [mg68104] simple antiderivative
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Tue, 25 Jul 2006 04:01:22 -0400 (EDT)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
You entered a wrong expression. Use Sec[x]^2 vice Sec^2[x] Integrate[8*x - 3*Sec[x]^2, x] 4*x^2 - 3*Tan[x] Bob Hanlon ---- T Harris <tdh1967 at bellsouth.net> wrote: > Hello, I am a beginner with Mathematica and I am wrapping up Calculus 1 > right now. Here is my question. > > I am doing antiderivatives and tried to check one I did and can't get my > handworked answer which is correct by the solution manual to match > Mathematica's > answer. I copied and pasted everything here so it looks weird until you > paste it back in notebook. > > Here is my input copied and pasted; > > \!\(Integrate[8 x - 3\ \(Sec\^2\)[x], x]\) > > My output is : > > \!\(\[Integral]\((8\ x - 3\ \(Sec\^2\)[x])\) \[DifferentialD]x\) > > Why don't I get the answer below as I do when I do it by hand? The > antiderivative of Sec^2 is Tan. I am puzzled by the output mathematica > gives. > > \!\(4 x\^2 - 3\ Tan\ [x]\) > > > Thanks > > T Harris >