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Re: v. 6, third argument to rectangle

  • To: mathgroup at smc.vnet.net
  • Subject: [mg76796] Re: v. 6, third argument to rectangle
  • From: rip pelletier <bitbucket at comcast.net>
  • Date: Sun, 27 May 2007 05:05:03 -0400 (EDT)
  • References: <f21e5e$6e7$1@smc.vnet.net> <f38qk4$hrc$1@smc.vnet.net>

In article <f38qk4$hrc$1 at smc.vnet.net>, dimitris <dimmechan at yahoo.com> 
wrote:

hi dimitris,

thanks for the suggestion, but GraphicsGrid is extremely simple and does 
exactly what i want.

vale,
   rip

> I think the following was not mentioned.
> 
> Since you are interested in putting two graphs side by side what is
> bad with the following
> 
> In[73]:=
> Block[{$DisplayFunction = Identity}, g1 = Plot[o^(1/2), {o, 1, 2},
> PlotStyle -> Red];
>    g2 = Plot[Log[o], {o, 1, 2}, PlotStyle -> Blue]; ]
> Show[GraphicsArray[{g1, g2}], ImageSize -> 600]
> 
> It works in version 5.2 and I think there will not be any problem in
> version 6. (confirmation needed!)
> 
> Dimitris
> 
>  /  rip pelletier       :
> > hi,
> >
> > thru 5.2 we could display, for example, 2 graphs side-by-side by using a
> > third argument to Rectangle, the name of a graphics object.
> >
> > 6.0 tells me that i cannot call Rectangle with 3 arguments. (true, it
> > was a bit of a kludge, and in principle i approve of it going away,
> > but....)
> >
> > what is the replacement?
> >
> > thanks,
> >    rip
> >
> > --
> > NB eddress is r i p 1 AT c o m c a s t DOT n e t

-- 
NB eddress is r i p 1 AT c o m c a s t DOT n e t


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