       Re: Partial Differentiation of Implicit Functions

• To: mathgroup at smc.vnet.net
• Subject: [mg83277] Re: Partial Differentiation of Implicit Functions
• From: "Jay" <jay at aleka.freeserve.co.uk>
• Date: Fri, 16 Nov 2007 05:41:44 -0500 (EST)
• Organization: Helsinki Television
• References: <fhc3pe\$510\$1@smc.vnet.net>

```Thanks guys. Seems I had got confused between the use of 'Solve' and
'Eliminate'

Jay.

"Jay" <jay at aleka.freeserve.co.uk> wrote in message
news:fhc3pe\$510\$1 at smc.vnet.net...
> Hi,
>
> I have some equations of the form:
> AA x^2 + BB y^2 + CC z^2 + DD x y +EE x z + FF y z + GG x + HH y + II z +
> JJ== 0
>
> I want to solve for e.g. partial dy/dz = 0 and then combine the result
> with
> the original equation to get a new implicit equation.
>
> E.g.
>
> E1 := -2 + x^2 + x z + y^2 + z^2
>
> (where I require E1 == 0)
>
> Manually performing the differentiation gives:
>
> partial dx/dz (y constant) = (x+2 z)/(2x + z) == 0
>
> I can then go back into mathematica and do
>
> Eliminate[{E1 == 0, 2*z + x == 0}, {z}]
>
> giving:
>
> 4 x y + 4 y^2 == 8 - 5 x^2
>
> This is what I want but how do I do everything in Mathematica? I expected
> to
> be able to do something like:
>
>  Solve[E1==0,D[x,y]]
>
> but it doesn't seem to work (says "0" is not a valid variable)
>
> Thanks,
>
> Jay.
>
>
>
>
>
>
>

```

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