Re: Controlling evaluation
- To: mathgroup at smc.vnet.net
- Subject: [mg83721] Re: Controlling evaluation
- From: Albert Retey <awnl at arcor.net>
- Date: Thu, 29 Nov 2007 06:19:28 -0500 (EST)
- References: <fiji6s$ikm$1@smc.vnet.net>
magma wrote:
> I am building a package and I need to programmatically construct
> expressions .
> At a certain point I have
>
> arg1 = {a, b, c}; (* some list *)
> arg2 = {d, e, f}; (* some other list *)
> samelistQ[list1_List, list2_List] :=
> list1 === list2 (* some logic function *)
>
> Now I want to construct an expression like
>
> Condition[expr, samelistQ[arg1, arg2]]
>
> with arg1 and arg2 evaluated, but with samelist[...] not evaluated.
> In other words, I want to obtain exactly this
>
> Condition[expr, samelistQ[{a, b, c}, {d, e, f}]]
>
> where the 2 args have been evaluated, but samelistQ[...] appears
> always unevaluated
> What is expr is not important, just leave it unassigned.
> The problem is that Condition blocks the evaluation of arg1 and arg2
> and of samelistQ.
>
> Now, doing
>
> Condition[expr, samelistQ[arg1 // Evaluate, arg2 // Evaluate]]
>
> does not work, because Evaluate does not disappear.
> So what to do? I tried Hold, ReleaseHold, ect, but it didn't work.
>
> This is how I solved it
>
> Condition @@ List[expr, pp[arg1, arg2]] /. pp -> samelistQ
>
> where pp is an unassigned symbol.
> My question: isn't there a better way, using the functions which are
> supposed to control evaluation (Hold, Evaluate, ect) to achieve this
> result?
I think the best thing for doing things like that is using With:
With[{a1 = arg1, a2 = arg2},
Condition[expr, samelistQ[a1, a2]]
]
> Perhaps a related more general question:
> how do we block
> f[x,y]
> while allowing evaluation of x, and y ?
With[{x=yexpr,y=xexpr},
Hold[f[x,y]]
]
hth,
albert