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Re: Re: branch of (-1)^(1/3)


slawek wrote:
> [...]
> Actually the solution is to redefine Power function in this way:
> 
>     Unprotect[Power]
>     Power[x_?Negative, Rational[p_, q_?OddQ]] := -(-x)^(p/q)
>     Protect[Power]
> 
> This is the answer from Technical Support Wolfram Research, Inc.
> [...]
> slawek

We get the answers we ask for. Kind'a like politics.

Daniel Lichtblau
Wolfram Research


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