Re: vector function of a vector
- To: mathgroup at smc.vnet.net
- Subject: [mg84705] Re: vector function of a vector
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Thu, 10 Jan 2008 05:35:46 -0500 (EST)
- Organization: Uni Leipzig
- References: <fm4hls$722$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi,
and you realy think we will find it out without
- knowing what tag is protected in your incomplete
error message
- knowing sNN,sphi or NN
- knowing what PoissonEq[] does ??
not Thursdays ..
Regards
Jens
Dmitri wrote:
> Here is what I want to do
>
> MyPoisson[sNN_, sphi_] :=
> Table[PoissonEq[sNN[[i]],
> sphi[[i + 1]],
> sphi[[i]],
> sphi[[i - 1]]],
> {i, 2, NN - 1}];
>
> but I get errror with "...protected tag". Here PoissonEq is just user defined delayed substitution.
>
>
> How do I get around this?
>
> More generally, I can create a list (MyPoisson) without any problems and evaluate it for specific values of the variables by using ReplaceAll operation. However it is very very slow operation. I could not make it work with Block operation unfortunately. This is why I want to have a function instead.
>
> Thanks a lot!
>