Re: DeleteCases
- To: mathgroup at smc.vnet.net
- Subject: [mg98193] Re: DeleteCases
- From: dh <dh at metrohm.com>
- Date: Thu, 2 Apr 2009 04:46:40 -0500 (EST)
- References: <gqsn69$3qp$1@smc.vnet.net>
Hi Filippo,
hope you had a good sleep.
You may use Union with SameTest. The firstcase may be implemented by:
Union[yourList,SameTest->({#[[3]],#[[3]],#1[[1]],#1[[1]]}==#2)&]
if you want additionally the second test, you would append it in the
function using Or (||).
Daniel
Filippo Miatto wrote:
> Dear all,
> Given this example list:
>
> {{0, 0, 1, 1}, {0, 0, 2, 2}, {0, 0, 3, 3}, {1, 1, 0, 0}, {1, 1, 2, 2},
> {1, 1, 3, 3}, {2, 2, 0, 0}, {2, 2, 1, 1}, {2, 2, 3, 3}, {3, 3, 0, 0},
> {3, 3, 1, 1}, {3, 3, 2, 2}}
>
> I need the elements {a,a,b,b} and {b,b,a,a} to be the same, i.e. i
> want to delete one of the two occurrences from the list. (or all but
> one if the condition is more complicated, say {a,b,c,d} and {b,a,c,d}
> or {a,b,c,d} and {a,b,d,c})
> How can i do that? Can i use DeleteCases? if so, what conditional
> should I use to compare different elements in the list?
> I tried without success for all the night.. (it's 6.15AM now!)
> Thank you,
>
> Filippo
>