Re: MeijerG
- To: mathgroup at smc.vnet.net
- Subject: [mg95175] Re: MeijerG
- From: dh <dh at metrohm.com>
- Date: Fri, 9 Jan 2009 06:21:30 -0500 (EST)
- References: <gk3fba$dt9$1@smc.vnet.net>
Hi Dimitris,
simply try it out numerically. E.g. setting c->1 you can use NLimit.
This is in agreement with "Limit". Therefore, it is certainly not
"Infinity". Or you could numerically calculate the value for different x
and c. This also agrees well with the solution from Limit.
Daniel
dimitris wrote:
> Can I trust the following result?
>
> In[29]:= Limit[-Log[x^2] -
> Sqrt[Pi]*MeijerG[{{0}, {}}, {{0, 0}, {1/2}}, x^2/(4*c)], x -> 0]
> (*c>0*)
>
> Out[29]= 2*EulerGamma + Log[1/c]
>
> Another well known CAS gave
>
>> limit(-ln(x^2)-sqrt(Pi)*MeijerG([[0], []],[[0, 0], [1/2]],1/4*x^2/c),x = 0);
>
>> infinity
>
>
> Regards
> Dimitris
>