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Re: MeijerG

  • To: mathgroup at smc.vnet.net
  • Subject: [mg95175] Re: MeijerG
  • From: dh <dh at metrohm.com>
  • Date: Thu, 8 Jan 2009 06:43:23 -0500 (EST)
  • References: <gk3fba$dt9$1@smc.vnet.net>


Hi Dimitris,

simply try it out numerically. E.g. setting c->1 you can use NLimit. 

This is in agreement with "Limit". Therefore, it is certainly not 

"Infinity". Or you could numerically calculate the value for different x 

and c. This also agrees well with the solution from Limit.

Daniel



dimitris wrote:

> Can I trust the following result?

> 

> In[29]:= Limit[-Log[x^2] -

>   Sqrt[Pi]*MeijerG[{{0}, {}}, {{0, 0}, {1/2}}, x^2/(4*c)], x -> 0]

> (*c>0*)

> 

> Out[29]= 2*EulerGamma + Log[1/c]

> 

> Another well known CAS gave

> 

>> limit(-ln(x^2)-sqrt(Pi)*MeijerG([[0], []],[[0, 0], [1/2]],1/4*x^2/c),x = 0);

> 

>>                              infinity

> 

> 

> Regards

> Dimitris

> 




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