Re: Distributing square-root (1/2) power through exponential equation
- To: mathgroup at smc.vnet.net
- Subject: [mg101306] Re: Distributing square-root (1/2) power through exponential equation
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Wed, 1 Jul 2009 06:31:52 -0400 (EDT)
- Organization: Uni Leipzig
- References: <h2cprm$agj$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi, Dist = Sqrt[SqD] // PowerExpand does not what you want ? Regards Jens Steven Matthew Anderson wrote: > I'm playing with normal distributions, Two random points 1 and 2 with x and y coordinates given by: > > px1=PDF[NormalDistribution[Mu,Sx],X1] > px2=PDF[NormalDistribution[Mu,Sx],X1] > py1=PDF[NormalDistribution[Mu,Sy],Y1] > py2=PDF[NormalDistribution[Mu,Sy],Y2] > > The square of the Euclidean Distance between them is > > SqD = (px2-px1)^2+(py2-py1)^2 > > Take the square root and expand of that to get > > Dist = Sqrt[Expand[SqD]] > > Now the question: > > How do I get the square root to act just like another power so I can simplify this mess? I have tried PowerExpand, FullSimplify, Expand, Simplify, and various combinations. Not sure what I'm missing here. >