Re: For loops with mathematica....
- To: mathgroup at smc.vnet.net
- Subject: [mg101128] Re: [mg101069] For loops with mathematica....
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Wed, 24 Jun 2009 06:36:35 -0400 (EDT)
- Reply-to: hanlonr at cox.net
Table[i^2, {i, Flatten[{Range[20, 200, 30], Range[300, 400, 25]}]}]
Do[y = i^2; Print[y];
Print[i == Sqrt[y]], {i,
Flatten[{Range[20, 200, 30], Range[300, 400, 25]}]}]
Bob Hanlon
---- Julien <jderr at cgr.harvard.edu> wrote:
=============
Hey guys,
I am totally new to mathematica.
I want to use a simple loop for but with many arguments in the loop...
the help says to do
Do[ thingstodo, {i,8}]
i will go from 1 to 8 to do thingstodo.
First question: what if I want i to go from 20 then 200 then 300 then 400, (can we give a sequence as argument?)
Second question: I have a lot of line to do in things to do. should I separate everything with a ; (doesn t seem to work, or use a procedure or something?)
THanks a lot for your help!!!
Julien