       Re: Inverse function

• To: mathgroup at smc.vnet.net
• Subject: [mg99378] Re: Inverse function
• From: dh <dh at metrohm.com>
• Date: Mon, 4 May 2009 06:01:13 -0400 (EDT)
• References: <gth5gc\$evb\$1@smc.vnet.net>

```
Hi,

InverseFunction is only a symbolic inverse. To get the inverse of a

function you may use e.g. Solve or in more complicated cases Reduce.

sol=Solve[y == 5/(2 - x), x]

You may write this as a function by e.g.:

fun = Evaluate[x /. sol[] /. y -> #] &

with this:

f evaluates to -3

Daniel

davef wrote:

> I have two questions:

>

> 1. Is it possible to find the inveses function for one-to-one function in Mathematica 7?

>

> For example the inverse of 5/(2-x) is 2-(5/x). I have tried Inverse and InverseFunction but I cannot produce the inverse function.

>

> Can anyone explain how to get Mathematica to produce this result? (See attached output screenshot.)

>

>

> 2. Is it possible to change the format of the output for a recprical?

>

> For example, instead of writing the output of Inverse[5/(2-x)] as (5/(2-x))^-1, can the output be set to produce (2-x)/5?

>

```

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