Re: Sort within self-defined procedure
- To: mathgroup at smc.vnet.net
- Subject: [mg108621] Re: Sort within self-defined procedure
- From: "Hans Michel" <hmichel at cox.net>
- Date: Thu, 25 Mar 2010 04:27:20 -0500 (EST)
- References: <hocm9o$shi$1@smc.vnet.net>
dornakul:
Try changing the "=" with ":=" please note the colon.
You are using the Mathematica symbol/function Set over Mathematica
symbol/function SetDelayed. For example
kz[x_] := Module[{l}, l = {1, 5, x, 2};
Sort[l, Greater]]
In[5]:= kz[20]
Out[5]= {20,5,2,1}
It is very cumbersome to use Mathematica without using shortcuts as most
examples go against this grain. But for learning differences between
functions/symbols or shortcuts I find it useful to use this form
SetDelayed[kt[x_], Module[{l},l={1,5,x,2};
Sort[l,Greater]]]
In[12]:= kt[30]
Out[12]= {30,5,2,1}
Now if you try to figure out how to do the entire process without using any
shortcuts such as "x_" you'll end up frustrated but learn alot about
Mathematica.
Hans
Hint
see
http://reference.wolfram.com/mathematica/tutorial/OperatorInputForms.html
SetDelayed[kr[Pattern[x, Blank[ ] ] ], Module[{l}, l = {1, 5, x, 2};
Sort[l, Greater]]]
"dornakul" <postitdummy at arcor.de> wrote in message
news:hocm9o$shi$1 at smc.vnet.net...
> Hi,
>
> I am desperate. Why is it not possible to sort a list within a self-
> defined procedure?
>
> Here comes the minimal example
>
> In[188]:= ks[x_] = Module[{l},
> l = {1, 5, x, 2};
> Sort[l, Greater]
> ]
>
> Out[188]= {5, x, 2, 1}
>
> In[190]:= ks[20]
>
> Out[190]= {5, 20, 2, 1}
>
> Dornakul
> Using Mathematica 7 on a Windows machine
>