Re: Plot this?
- To: mathgroup at smc.vnet.net
- Subject: [mg109549] Re: Plot this?
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Wed, 5 May 2010 06:04:12 -0400 (EDT)
It's really a question of what kind of plot you want, since you do not
have either x or y as an explicit function of x. Moreover, it's unclear
whether you want to regard this as a 2-dimensional curve or as a
3-dimensional surface. In either case, some version of a contour plot
will directly give what I think you are asking for:
ContourPlot[8x -x^2 + 14y - y^2 == 49, {x, 0, 12}, {y, 0, 12},
Frame->False, Axes->True, AxesLabel->{x,y}]
ContourPlot3D[8x - x^2 + 14y - y^2 == 49, {x,0,10}, {y,0,12}, {z,-5,5},
AxesLabel->{x,y,z}]
On 5/4/2010 6:30 AM, Trevor Rabey wrote:
> I am new to Mathematica and going at snail's pace.
> I would like to plot:
>
> 8x - x^2 + 14y - y^2 = 49
>
> Anyone?
>
> --
> Trevor Rabey
>
--
Murray Eisenberg murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower phone 413 549-1020 (H)
University of Massachusetts 413 545-2859 (W)
710 North Pleasant Street fax 413 545-1801
Amherst, MA 01003-9305