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Re: Interpolate in polar coordinates or cartesian

• To: mathgroup at smc.vnet.net
• Subject: [mg112763] Re: Interpolate in polar coordinates or cartesian
• From: "u31815170" <ingolf.dahl at telia.com>
• Date: Wed, 29 Sep 2010 04:16:30 -0400 (EDT)

Hi Szymon,
You might do this without my package with

Show[{ListPlot3D[Data,
   PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}},
   MeshFunctions -> {#3 &}, Mesh -> {Range[-0.1, 0.6, 0.1]}],
  ListPointPlot3D[Data,
   PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}}]}]

or with my package and with definitions below (shows more detail, takes some
time)

test == Interpolation[Data1, Method -> "ObtuseAngle",
  InterpolationOrder -> 2];
Show[{Plot3D[test[{x, y}], {x, -0.3, 0.3}, {y, -0.3, 0.3},
   PlotRange -> {-0.1, 0.6}, MeshFunctions -> {#3 &},
   Mesh -> {Range[-0.1, 0.6, 0.1]}, PlotPoints -> 30],
  ListPointPlot3D[Data,
   PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}}]}]

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Best regards

Ingolf Dahl
ingolf.dahl at telia.com

-----Ursprungligt meddelande-----
Fr=E5n: Szymon Roziewski [mailto:szymon.roziewski at gmail.com]
Skickat: den 28 september 2010 12:06
Till: mathgroup at smc.vnet.net
=C4mne: [mg112728] Re: Interpolate in polar coordinates or cartesian

hi there,
the interpolation works fine now,
but I wonder whether it is possible to make a contour lines on Plot3D curve=

• Follow-Ups:
  • Re: Interpolate in polar coordinates or cartesian
    • From: Szymon Roziewski <szymon.roziewski@gmail.com>