Re: Interpolate in polar coordinates or cartesian
- To: mathgroup at smc.vnet.net
- Subject: [mg112771] Re: Interpolate in polar coordinates or cartesian
- From: Szymon Roziewski <szymon.roziewski at gmail.com>
- Date: Thu, 30 Sep 2010 04:50:03 -0400 (EDT)
- References: <201009290816.EAA28232@smc.vnet.net>
Hello, Thank You very much for your solutions. I have such a problem namely, how I can find a maximum of interpolated function test? NMaximize doesn't work - it's surprised during computations.. or I do sth wrong... This is the output: NMaximize[test0[{x, y}], {x, y}] HierarchicalClustering`DistanceMatrix::amtd: -- Message text not found -- ({{x,y},{0.0108186,0.0403757}}) >> HierarchicalClustering`DistanceMatrix::amtd: -- Message text not found -- ({{x,y},{0.0295571,0.0295571}}) >> HierarchicalClustering`DistanceMatrix::amtd: -- Message text not found -- ({{x,y},{0.0403757,0.0108186}}) >> General::stop: Further output of HierarchicalClustering`DistanceMatrix::amtd will be suppressed during this calculation. >> 2010/9/29 u31815170 <ingolf.dahl at telia.com> > Hi Szymon, > You might do this without my package with > > Show[{ListPlot3D[Data, > PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}}, > MeshFunctions -> {#3 &}, Mesh -> {Range[-0.1, 0.6, 0.1]}], > ListPointPlot3D[Data, > PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}}]}] > > or with my package and with definitions below (shows more detail, takes > some > time) > > test == Interpolation[Data1, Method -> "ObtuseAngle", > InterpolationOrder -> 2]; > Show[{Plot3D[test[{x, y}], {x, -0.3, 0.3}, {y, -0.3, 0.3}, > PlotRange -> {-0.1, 0.6}, MeshFunctions -> {#3 &}, > Mesh -> {Range[-0.1, 0.6, 0.1]}, PlotPoints -> 30], > ListPointPlot3D[Data, > PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}}]}] > > This is sent from Outlook2007 as unformatted text > Best regards > > Ingolf Dahl > ingolf.dahl at telia.com > > -----Ursprungligt meddelande----- > Fr=E5n: Szymon Roziewski [mailto:szymon.roziewski at gmail.com] > Skickat: den 28 september 2010 12:06 > Till: mathgroup at smc.vnet.net > =C4mne: [mg112728] Re: Interpolate in polar coordinates or cartesian > > hi there, > the interpolation works fine now, > but I wonder whether it is possible to make a contour lines on Plot3D > curve= > -- Z wyrazami szacunku, Szymon Roziewski --0016e6db2d624aeb410491657e3d Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Hello,<br>Thank You very much for your solutions.<br>I have such a problem = namely, how I can find a maximum of interpolated function test?<br>NMaximiz= e doesn't work - it's surprised during computations.. or I do sth w= rong...<br> <br><br>This is the output:<br><br>NMaximize[test0[{x, y}], {x, y}]<br><br>= HierarchicalClustering`DistanceMatrix::amtd: -- Message text not found -- (= {{x,y},{0.0108186,0.0403757}}) >><br><br>HierarchicalClustering`Dista= nceMatrix::amtd: -- Message text not found -- ({{x,y},{0.0295571,0.0295571}= }) >><br> <br>HierarchicalClustering`DistanceMatrix::amtd: -- Message text not found = -- ({{x,y},{0.0403757,0.0108186}}) >><br><br>General::stop: Further o= utput of HierarchicalClustering`DistanceMatrix::amtd will be suppressed dur= ing this calculation. >><br> <br><br><br><div class="gmail_quote">2010/9/29 u31815170 <span dir="ltr= "><<a href="mailto:ingolf.dahl at telia.com">ingolf.dahl at telia.com</a>>= ;</span><br><blockquote class="gmail_quote" style="border-left: 1px sol= id rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"> <div class="im">Hi Szymon,<br> You might do this without my package with<br> <br> Show[{ListPlot3D[Data,<br> PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}},<br> MeshFunctions -> {#3 &}, Mesh -> {Range[-0.1, 0.6, 0.1]}],<b= r> ListPointPlot3D[Data,<br> PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}}]}]<br> <br> or with my package and with definitions below (shows more detail, takes som= e<br> time)<br> <br> test == Interpolation[Data1, Method -> "ObtuseAngle",<br> InterpolationOrder -> 2];<br> Show[{Plot3D[test[{x, y}], {x, -0.3, 0.3}, {y, -0.3, 0.3},<br> PlotRange -> {-0.1, 0.6}, MeshFunctions -> {#3 &},<br> Mesh -> {Range[-0.1, 0.6, 0.1]}, PlotPoints -> 30],<br> ListPointPlot3D[Data,<br> PlotRange -> {{-0.3, 0.3}, {-0.3, 0.3}, {-0.1, 0.6}}]}]<br> <br> This is sent from Outlook2007 as unformatted text<br> Best regards<br> <br> Ingolf Dahl<br> <a href="mailto:ingolf.dahl at telia.com">ingolf.dahl at telia.com</a><br> <br> -----Ursprungligt meddelande-----<br> </div><div class="im">Fr=E5n: Szymon Roziewski [mailto:<a href="mailt= o:szymon.roziewski at gmail.com">szymon.roziewski at gmail.com</a>]<br> </div><div class="im">Skickat: den 28 september 2010 12:06<br> Till: <a href="mailto:mathgroup at smc.vnet.net">mathgroup at smc.vnet.net</a><= br> </div>=C4mne: [mg112728] Re: Interpolate in polar coordinates or cartesia= n<br> <div class="im"><br> hi there,<br> the interpolation works fine now,<br> </div>but I wonder whether it is possible to make a contour lines on Plot3D= curve=<br> </blockquote></div><br><br clear="all"><br>-- <br>Z wyrazami szacunku,<br= >Szymon Roziewski<br> --0016e6db2d624aeb410491657e3d--
- References:
- Re: Interpolate in polar coordinates or cartesian
- From: "u31815170" <ingolf.dahl@telia.com>
- Re: Interpolate in polar coordinates or cartesian