       Re: Just another Mathematica "Gotcha"

• To: mathgroup at smc.vnet.net
• Subject: [mg120802] Re: Just another Mathematica "Gotcha"
• From: Bill Rowe <readnews at sbcglobal.net>
• Date: Wed, 10 Aug 2011 06:48:51 -0400 (EDT)
• Delivered-to: l-mathgroup@mail-archive0.wolfram.com

```On 8/9/11 at 7:19 AM, siegman at stanford.edu (AES) wrote:

>Seems as if the following two expression should yield the same
>output -- seems that way to me anyway -- but they don't.  I'll hide
>the actual outputs down below so Mathematica gurus (or "ordinary
>users") can make their predictions as to which one does what.

>In:= Series[a+(b1+b2)x,{x,0,1}] //Normal /.{b2->0}

>In:= Series[a+(b1+b2)x,{x,0,1}] /.{b2->0} //Normal

>My conclusions:

>1)  By any normal rules of interpretation or ordinary
>interpretations of these statements, they both should do the same
>same thing.

If and only if the // and /. operators had the same precedence
this would be true. But since /. has higher precedence than //

Series[a+(b1+b2)x,{x,0,1}] //Normal /.{b2->0}

is equivalent to

Series[a+(b1+b2)x,{x,0,1}] //(Normal /.{b2->0})

rather thab

(Series[a+(b1+b2)x,{x,0,1}])//Normal /.{b2->0}

The problem here is exactly analogous to why

a + b * c

doesn't yield (a+b)*c

>2)  This is just another Mathematica "Gotcha" -- and not a
>particularly forgivable one.

No, this is simply a failure on your part to understand operator precedence.

```

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