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Re: Inverse Interpolation

  • To: mathgroup at smc.vnet.net
  • Subject: [mg120966] Re: Inverse Interpolation
  • From: Fred Simons <f.h.simons at tue.nl>
  • Date: Fri, 19 Aug 2011 06:34:35 -0400 (EDT)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <201108180722.DAA11854@smc.vnet.net>

The points used by the function Plot can be found in the plot itself:

With[{gr = Plot[Cos[x], {x, -1, 1}]},  Cases[gr, Line[x_] :> x, 
Infinity][[1]]]

Regards,

Fred Simons
Eindhoven University of Technology

Op 18-8-2011 9:22, WetBlanket schreef:
> Previously, the following code could be used to use the Plot functions
> algorithm to select point at which to evaluate a function to assist in
> obtaining a good numerical interpolation.  In Version 8 this code does
> not seem to work ( at least for me).  Can someone assist me by showing
> how this task is best accomplished in Version 8.  I use the Cos
> function in this example for simplicity.  Clearly, numerical
> interpolation is not needed to obtain an inverse for the Cos.
>
> list={};
> F = Cos[x];
>
> Plot[ (  ss=F;  AppendTo[list, {ss,x}]; ss), {x,-1,1}, PlotPoints-
>> 1000,
> PlotRange->All, AxesLabel->{"x","F"}]
>
> Thanks for the help.
>
>





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